n(n-3)=7*(4)

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Solution for n(n-3)=7*(4) equation:


Simplifying
n(n + -3) = 7(4)

Reorder the terms:
n(-3 + n) = 7(4)
(-3 * n + n * n) = 7(4)
(-3n + n2) = 7(4)

Multiply 7 * 4
-3n + n2 = 28

Solving
-3n + n2 = 28

Solving for variable 'n'.

Reorder the terms:
-28 + -3n + n2 = 28 + -28

Combine like terms: 28 + -28 = 0
-28 + -3n + n2 = 0

Factor a trinomial.
(-4 + -1n)(7 + -1n) = 0

Subproblem 1

Set the factor '(-4 + -1n)' equal to zero and attempt to solve: Simplifying -4 + -1n = 0 Solving -4 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1n = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1n = 0 + 4 -1n = 0 + 4 Combine like terms: 0 + 4 = 4 -1n = 4 Divide each side by '-1'. n = -4 Simplifying n = -4

Subproblem 2

Set the factor '(7 + -1n)' equal to zero and attempt to solve: Simplifying 7 + -1n = 0 Solving 7 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1n = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1n = 0 + -7 -1n = 0 + -7 Combine like terms: 0 + -7 = -7 -1n = -7 Divide each side by '-1'. n = 7 Simplifying n = 7

Solution

n = {-4, 7}

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