n*(n+1)+(n+2)*(n+3)+1=0

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Solution for n*(n+1)+(n+2)*(n+3)+1=0 equation: 



n(n+1)+(n+2)(n+3)+1=0

We multiply parentheses

n^2+n+(n+2)(n+3)+1=0

We multiply parentheses ..

n^2+(+n^2+3n+2n+6)+n+1=0

We get rid of parentheses

n^2+n^2+3n+2n+n+6+1=0

We add all the numbers together, and all the variables

2n^2+6n+7=0

a = 2; b = 6; c = +7;
Δ = b2-4ac
Δ = 62-4·2·7
Δ = -20
Delta is less than zero, so there is no solution for the equation

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