n*2x+(n+1)*x=100

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Solution for n*2x+(n+1)*x=100 equation:


Simplifying
n * 2x + (n + 1) * x = 100

Reorder the terms for easier multiplication:
2n * x + (n + 1) * x = 100

Multiply n * x
2nx + (n + 1) * x = 100

Reorder the terms:
2nx + (1 + n) * x = 100

Reorder the terms for easier multiplication:
2nx + x(1 + n) = 100
2nx + (1 * x + n * x) = 100

Reorder the terms:
2nx + (nx + 1x) = 100
2nx + (nx + 1x) = 100

Combine like terms: 2nx + nx = 3nx
3nx + 1x = 100

Solving
3nx + 1x = 100

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-1x' to each side of the equation.
3nx + 1x + -1x = 100 + -1x

Combine like terms: 1x + -1x = 0
3nx + 0 = 100 + -1x
3nx = 100 + -1x

Divide each side by '3x'.
n = 33.33333333x-1 + -0.3333333333

Simplifying
n = 33.33333333x-1 + -0.3333333333

Reorder the terms:
n = -0.3333333333 + 33.33333333x-1

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