n*3-1*4=n*12+1*2

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Solution for n*3-1*4=n*12+1*2 equation:


Simplifying
n * 3 + -1 * 4 = n * 12 + 1 * 2

Reorder the terms for easier multiplication:
3n + -1 * 4 = n * 12 + 1 * 2

Multiply -1 * 4
3n + -4 = n * 12 + 1 * 2

Reorder the terms:
-4 + 3n = n * 12 + 1 * 2

Reorder the terms for easier multiplication:
-4 + 3n = 12n + 1 * 2

Multiply 1 * 2
-4 + 3n = 12n + 2

Reorder the terms:
-4 + 3n = 2 + 12n

Solving
-4 + 3n = 2 + 12n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-12n' to each side of the equation.
-4 + 3n + -12n = 2 + 12n + -12n

Combine like terms: 3n + -12n = -9n
-4 + -9n = 2 + 12n + -12n

Combine like terms: 12n + -12n = 0
-4 + -9n = 2 + 0
-4 + -9n = 2

Add '4' to each side of the equation.
-4 + 4 + -9n = 2 + 4

Combine like terms: -4 + 4 = 0
0 + -9n = 2 + 4
-9n = 2 + 4

Combine like terms: 2 + 4 = 6
-9n = 6

Divide each side by '-9'.
n = -0.6666666667

Simplifying
n = -0.6666666667

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