n+(1/n)=(17/4)

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Solution for n+(1/n)=(17/4) equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

n+1/n = 17/4 // - 17/4

n+1/n-(17/4) = 0

n+1/n-17/4 = 0

1*n^1+1*n^-1-17/4*n^0 = 0

(1*n^2-17/4*n^1+1*n^0)/(n^1) = 0 // * n^2

n^1*(1*n^2-17/4*n^1+1*n^0) = 0

n^1

n^2+(-17/4)*n+1 = 0

n^2+(-17/4)*n+1 = 0

DELTA = (-17/4)^2-(1*1*4)

DELTA = 225/16

DELTA > 0

n = ((225/16)^(1/2)-(-17/4))/(1*2) or n = (-(-17/4)-(225/16)^(1/2))/(1*2)

n = 4 or n = 1/4

n in { 1/4, 4} 

n in { 1/4, 4 }

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