n+(2+4n)-6=63

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Solution for n+(2+4n)-6=63 equation: 



n+(2+4n)-6=63

We move all terms to the left:

n+(2+4n)-6-(63)=0

We add all the numbers together, and all the variables

n+(4n+2)-6-63=0

We add all the numbers together, and all the variables

n+(4n+2)-69=0

We get rid of parentheses

n+4n+2-69=0

We add all the numbers together, and all the variables

5n-67=0

We move all terms containing n to the left, all other terms to the right

5n=67

n=67/5

n=13+2/5

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