n+(2n-3)/6=3

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Solution for n+(2n-3)/6=3 equation: 



n+(2n-3)/6=3

We move all terms to the left:

n+(2n-3)/6-(3)=0

We multiply all the terms by the denominator


n*6+(2n-3)-3*6=0

We add all the numbers together, and all the variables

n*6+(2n-3)-18=0

Wy multiply elements

6n+(2n-3)-18=0

We get rid of parentheses

6n+2n-3-18=0

We add all the numbers together, and all the variables

8n-21=0

We move all terms containing n to the left, all other terms to the right

8n=21

n=21/8

n=2+5/8

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