n+(2n-5)=28

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Solution for n+(2n-5)=28 equation:



n+(2n-5)=28
We move all terms to the left:
n+(2n-5)-(28)=0
We get rid of parentheses
n+2n-5-28=0
We add all the numbers together, and all the variables
3n-33=0
We move all terms containing n to the left, all other terms to the right
3n=33
n=33/3
n=11

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