n+(3n-15)=101

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Solution for n+(3n-15)=101 equation: 



n+(3n-15)=101

We move all terms to the left:

n+(3n-15)-(101)=0

We get rid of parentheses

n+3n-15-101=0

We add all the numbers together, and all the variables

4n-116=0

We move all terms containing n to the left, all other terms to the right

4n=116

n=116/4

n=29

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