n+(3n-15)=101

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Solution for n+(3n-15)=101 equation:



n+(3n-15)=101
We move all terms to the left:
n+(3n-15)-(101)=0
We get rid of parentheses
n+3n-15-101=0
We add all the numbers together, and all the variables
4n-116=0
We move all terms containing n to the left, all other terms to the right
4n=116
n=116/4
n=29

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