n+(3n-4)=100

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Solution for n+(3n-4)=100 equation: 



n+(3n-4)=100

We move all terms to the left:

n+(3n-4)-(100)=0

We get rid of parentheses

n+3n-4-100=0

We add all the numbers together, and all the variables

4n-104=0

We move all terms containing n to the left, all other terms to the right

4n=104

n=104/4

n=26

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