n+(n+1)+(n+2)+(n+3)+(n+4)=55

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Solution for n+(n+1)+(n+2)+(n+3)+(n+4)=55 equation:



n+(n+1)+(n+2)+(n+3)+(n+4)=55
We move all terms to the left:
n+(n+1)+(n+2)+(n+3)+(n+4)-(55)=0
We get rid of parentheses
n+n+n+n+n+1+2+3+4-55=0
We add all the numbers together, and all the variables
5n-45=0
We move all terms containing n to the left, all other terms to the right
5n=45
n=45/5
n=9

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