n+(n+1)+(n+2)+(n+3)=54

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Solution for n+(n+1)+(n+2)+(n+3)=54 equation: 



n+(n+1)+(n+2)+(n+3)=54

We move all terms to the left:

n+(n+1)+(n+2)+(n+3)-(54)=0

We get rid of parentheses

n+n+n+n+1+2+3-54=0

We add all the numbers together, and all the variables

4n-48=0

We move all terms containing n to the left, all other terms to the right

4n=48

n=48/4

n=12

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