n+(n+1)+(n+2)=132

Solution for n+(n+1)+(n+2)=132 equation:

Simplifying
n + (n + 1) + (n + 2) = 132

Reorder the terms:
n + (1 + n) + (n + 2) = 132

Remove parenthesis around (1 + n)
n + 1 + n + (n + 2) = 132

Reorder the terms:
n + 1 + n + (2 + n) = 132

Remove parenthesis around (2 + n)
n + 1 + n + 2 + n = 132

Reorder the terms:
1 + 2 + n + n + n = 132

Combine like terms: 1 + 2 = 3
3 + n + n + n = 132

Combine like terms: n + n = 2n
3 + 2n + n = 132

Combine like terms: 2n + n = 3n
3 + 3n = 132

Solving
3 + 3n = 132

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 3n = 132 + -3

Combine like terms: 3 + -3 = 0
0 + 3n = 132 + -3
3n = 132 + -3

Combine like terms: 132 + -3 = 129
3n = 129

Divide each side by '3'.
n = 43

Simplifying
n = 43