n+(n+1)+(n+2)=3(n+2)

Solution for n+(n+1)+(n+2)=3(n+2) equation:

Simplifying
n + (n + 1) + (n + 2) = 3(n + 2)

Reorder the terms:
n + (1 + n) + (n + 2) = 3(n + 2)

Remove parenthesis around (1 + n)
n + 1 + n + (n + 2) = 3(n + 2)

Reorder the terms:
n + 1 + n + (2 + n) = 3(n + 2)

Remove parenthesis around (2 + n)
n + 1 + n + 2 + n = 3(n + 2)

Reorder the terms:
1 + 2 + n + n + n = 3(n + 2)

Combine like terms: 1 + 2 = 3
3 + n + n + n = 3(n + 2)

Combine like terms: n + n = 2n
3 + 2n + n = 3(n + 2)

Combine like terms: 2n + n = 3n
3 + 3n = 3(n + 2)

Reorder the terms:
3 + 3n = 3(2 + n)
3 + 3n = (2 * 3 + n * 3)
3 + 3n = (6 + 3n)

Add '-3n' to each side of the equation.
3 + 3n + -3n = 6 + 3n + -3n

Combine like terms: 3n + -3n = 0
3 + 0 = 6 + 3n + -3n
3 = 6 + 3n + -3n

Combine like terms: 3n + -3n = 0
3 = 6 + 0
3 = 6

Solving
3 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.