n+(n+2)+(n+3)=132

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Solution for n+(n+2)+(n+3)=132 equation:


n+(n+2)+(n+3)=132

We simplify the equation to the form, which is simple to understand 
n+(n+2)+(n+3)=132

Remove unnecessary parentheses
+n+n+2+(+n+3+)=+132

Remove unnecessary parentheses
+n+n+2+n+3=+132

We move all terms containing n to the left and all other terms to the right. 
+1n+1n+1n=+132-2-3

We simplify left and right side of the equation. 
+3n=+127

We divide both sides of the equation by 3 to get n. 
n=42.3333333333

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