n+(n+2)+(n+4)+(n+6)=200

Solution for n+(n+2)+(n+4)+(n+6)=200 equation:

Simplifying
n + (n + 2) + (n + 4) + (n + 6) = 200

Reorder the terms:
n + (2 + n) + (n + 4) + (n + 6) = 200

Remove parenthesis around (2 + n)
n + 2 + n + (n + 4) + (n + 6) = 200

Reorder the terms:
n + 2 + n + (4 + n) + (n + 6) = 200

Remove parenthesis around (4 + n)
n + 2 + n + 4 + n + (n + 6) = 200

Reorder the terms:
n + 2 + n + 4 + n + (6 + n) = 200

Remove parenthesis around (6 + n)
n + 2 + n + 4 + n + 6 + n = 200

Reorder the terms:
2 + 4 + 6 + n + n + n + n = 200

Combine like terms: 2 + 4 = 6
6 + 6 + n + n + n + n = 200

Combine like terms: 6 + 6 = 12
12 + n + n + n + n = 200

Combine like terms: n + n = 2n
12 + 2n + n + n = 200

Combine like terms: 2n + n = 3n
12 + 3n + n = 200

Combine like terms: 3n + n = 4n
12 + 4n = 200

Solving
12 + 4n = 200

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 4n = 200 + -12

Combine like terms: 12 + -12 = 0
0 + 4n = 200 + -12
4n = 200 + -12

Combine like terms: 200 + -12 = 188
4n = 188

Divide each side by '4'.
n = 47

Simplifying
n = 47