n+(n+2)+(n+4)+(n+6)=56

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Solution for n+(n+2)+(n+4)+(n+6)=56 equation: 



n+(n+2)+(n+4)+(n+6)=56

We move all terms to the left:

n+(n+2)+(n+4)+(n+6)-(56)=0

We get rid of parentheses

n+n+n+n+2+4+6-56=0

We add all the numbers together, and all the variables

4n-44=0

We move all terms containing n to the left, all other terms to the right

4n=44

n=44/4

n=11

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