n+(n+2)+(n+4)=96

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Solution for n+(n+2)+(n+4)=96 equation: 



n+(n+2)+(n+4)=96

We move all terms to the left:

n+(n+2)+(n+4)-(96)=0

We get rid of parentheses

n+n+n+2+4-96=0

We add all the numbers together, and all the variables

3n-90=0

We move all terms containing n to the left, all other terms to the right

3n=90

n=90/3

n=30

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