n+(n+2)+(n+40)=42

Solution for n+(n+2)+(n+40)=42 equation:

Simplifying
n + (n + 2) + (n + 40) = 42

Reorder the terms:
n + (2 + n) + (n + 40) = 42

Remove parenthesis around (2 + n)
n + 2 + n + (n + 40) = 42

Reorder the terms:
n + 2 + n + (40 + n) = 42

Remove parenthesis around (40 + n)
n + 2 + n + 40 + n = 42

Reorder the terms:
2 + 40 + n + n + n = 42

Combine like terms: 2 + 40 = 42
42 + n + n + n = 42

Combine like terms: n + n = 2n
42 + 2n + n = 42

Combine like terms: 2n + n = 3n
42 + 3n = 42

Add '-42' to each side of the equation.
42 + -42 + 3n = 42 + -42

Combine like terms: 42 + -42 = 0
0 + 3n = 42 + -42
3n = 42 + -42

Combine like terms: 42 + -42 = 0
3n = 0

Solving
3n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Divide each side by '3'.
n = 0

Simplifying
n = 0