n+(n+2)=24-4(n+4)

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Solution for n+(n+2)=24-4(n+4) equation: 


Simplifying
n + (n + 2) = 24 + -4(n + 4)

Reorder the terms:
n + (2 + n) = 24 + -4(n + 4)

Remove parenthesis around (2 + n)
n + 2 + n = 24 + -4(n + 4)

Reorder the terms:
2 + n + n = 24 + -4(n + 4)

Combine like terms: n + n = 2n
2 + 2n = 24 + -4(n + 4)

Reorder the terms:
2 + 2n = 24 + -4(4 + n)
2 + 2n = 24 + (4 * -4 + n * -4)
2 + 2n = 24 + (-16 + -4n)

Combine like terms: 24 + -16 = 8
2 + 2n = 8 + -4n

Solving
2 + 2n = 8 + -4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '4n' to each side of the equation.
2 + 2n + 4n = 8 + -4n + 4n

Combine like terms: 2n + 4n = 6n
2 + 6n = 8 + -4n + 4n

Combine like terms: -4n + 4n = 0
2 + 6n = 8 + 0
2 + 6n = 8

Add '-2' to each side of the equation.
2 + -2 + 6n = 8 + -2

Combine like terms: 2 + -2 = 0
0 + 6n = 8 + -2
6n = 8 + -2

Combine like terms: 8 + -2 = 6
6n = 6

Divide each side by '6'.
n = 1

Simplifying
n = 1

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