n+(n+4)=21+(n+2)

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Solution for n+(n+4)=21+(n+2) equation: 



n+(n+4)=21+(n+2)

We move all terms to the left:

n+(n+4)-(21+(n+2))=0

We get rid of parentheses

n+n-(21+(n+2))+4=0



We calculate terms in parentheses: -(21+(n+2)), so:

21+(n+2)

determiningTheFunctionDomain
(n+2)+21

We get rid of parentheses

n+2+21

We add all the numbers together, and all the variables

n+23

Back to the equation:

-(n+23)



We add all the numbers together, and all the variables

2n-(n+23)+4=0

We get rid of parentheses

2n-n-23+4=0

We add all the numbers together, and all the variables

n-19=0

We move all terms containing n to the left, all other terms to the right

n=19

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