n+(n+4)=27+(n+2)

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Solution for n+(n+4)=27+(n+2) equation:



n+(n+4)=27+(n+2)
We move all terms to the left:
n+(n+4)-(27+(n+2))=0
We get rid of parentheses
n+n-(27+(n+2))+4=0
We calculate terms in parentheses: -(27+(n+2)), so:
27+(n+2)
determiningTheFunctionDomain (n+2)+27
We get rid of parentheses
n+2+27
We add all the numbers together, and all the variables
n+29
Back to the equation:
-(n+29)
We add all the numbers together, and all the variables
2n-(n+29)+4=0
We get rid of parentheses
2n-n-29+4=0
We add all the numbers together, and all the variables
n-25=0
We move all terms containing n to the left, all other terms to the right
n=25

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