n+(n+4)=27+(n+2)

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Solution for n+(n+4)=27+(n+2) equation: 



n+(n+4)=27+(n+2)

We move all terms to the left:

n+(n+4)-(27+(n+2))=0

We get rid of parentheses

n+n-(27+(n+2))+4=0



We calculate terms in parentheses: -(27+(n+2)), so:

27+(n+2)

determiningTheFunctionDomain
(n+2)+27

We get rid of parentheses

n+2+27

We add all the numbers together, and all the variables

n+29

Back to the equation:

-(n+29)



We add all the numbers together, and all the variables

2n-(n+29)+4=0

We get rid of parentheses

2n-n-29+4=0

We add all the numbers together, and all the variables

n-25=0

We move all terms containing n to the left, all other terms to the right

n=25

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