n+(n+4)=30+(n+2)

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Solution for n+(n+4)=30+(n+2) equation: 



n+(n+4)=30+(n+2)

We move all terms to the left:

n+(n+4)-(30+(n+2))=0

We get rid of parentheses

n+n-(30+(n+2))+4=0



We calculate terms in parentheses: -(30+(n+2)), so:

30+(n+2)

determiningTheFunctionDomain
(n+2)+30

We get rid of parentheses

n+2+30

We add all the numbers together, and all the variables

n+32

Back to the equation:

-(n+32)



We add all the numbers together, and all the variables

2n-(n+32)+4=0

We get rid of parentheses

2n-n-32+4=0

We add all the numbers together, and all the variables

n-28=0

We move all terms containing n to the left, all other terms to the right

n=28

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