n+(n-2)+(n+4)=38

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Solution for n+(n-2)+(n+4)=38 equation: 



n+(n-2)+(n+4)=38

We move all terms to the left:

n+(n-2)+(n+4)-(38)=0

We get rid of parentheses

n+n+n-2+4-38=0

We add all the numbers together, and all the variables

3n-36=0

We move all terms containing n to the left, all other terms to the right

3n=36

n=36/3

n=12

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