n+1+1-5=-8(n-3)+2(1+4n)

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Solution for n+1+1-5=-8(n-3)+2(1+4n) equation:



n+1+1-5=-8(n-3)+2(1+4n)
We move all terms to the left:
n+1+1-5-(-8(n-3)+2(1+4n))=0
We add all the numbers together, and all the variables
n-(-8(n-3)+2(4n+1))+1+1-5=0
We add all the numbers together, and all the variables
n-(-8(n-3)+2(4n+1))-3=0
We calculate terms in parentheses: -(-8(n-3)+2(4n+1)), so:
-8(n-3)+2(4n+1)
We multiply parentheses
-8n+8n+24+2
We add all the numbers together, and all the variables
26
Back to the equation:
-(26)
We add all the numbers together, and all the variables
n-29=0
We move all terms containing n to the left, all other terms to the right
n=29

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