n+2(n+1)=20(n+2)

Solution for n+2(n+1)=20(n+2) equation:

n+2(n+1)=20(n+2)

We move all terms to the left:

n+2(n+1)-(20(n+2))=0

We multiply parentheses

n+2n-(20(n+2))+2=0


We calculate terms in parentheses: -(20(n+2)), so:

20(n+2)

We multiply parentheses

20n+40

Back to the equation:

-(20n+40)


We add all the numbers together, and all the variables

3n-(20n+40)+2=0

We get rid of parentheses

3n-20n-40+2=0

We add all the numbers together, and all the variables

-17n-38=0

We move all terms containing n to the left, all other terms to the right

-17n=38

n=38/-17

n=-2+4/17