n+2(n+3)=4+4(n+1)

Solution for n+2(n+3)=4+4(n+1) equation:

n+2(n+3)=4+4(n+1)

We move all terms to the left:

n+2(n+3)-(4+4(n+1))=0

We multiply parentheses

n+2n-(4+4(n+1))+6=0


We calculate terms in parentheses: -(4+4(n+1)), so:

4+4(n+1)

determiningTheFunctionDomain
4(n+1)+4

We multiply parentheses

4n+4+4

We add all the numbers together, and all the variables

4n+8

Back to the equation:

-(4n+8)


We add all the numbers together, and all the variables

3n-(4n+8)+6=0

We get rid of parentheses

3n-4n-8+6=0

We add all the numbers together, and all the variables

-1n-2=0

We move all terms containing n to the left, all other terms to the right

-n=2

n=2/-1

n=-2