n+2(n-4)-1=-3(1-n)-6

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Solution for n+2(n-4)-1=-3(1-n)-6 equation: 



n+2(n-4)-1=-3(1-n)-6

We move all terms to the left:

n+2(n-4)-1-(-3(1-n)-6)=0

We add all the numbers together, and all the variables

n+2(n-4)-(-3(-1n+1)-6)-1=0

We multiply parentheses

n+2n-(-3(-1n+1)-6)-8-1=0



We calculate terms in parentheses: -(-3(-1n+1)-6), so:

-3(-1n+1)-6

We multiply parentheses

3n-3-6

We add all the numbers together, and all the variables

3n-9

Back to the equation:

-(3n-9)



We add all the numbers together, and all the variables

3n-(3n-9)-9=0

We get rid of parentheses

3n-3n+9-9=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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