n+23=2(n-5)

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Solution for n+23=2(n-5) equation: 



n+23=2(n-5)

We move all terms to the left:

n+23-(2(n-5))=0



We calculate terms in parentheses: -(2(n-5)), so:

2(n-5)

We multiply parentheses

2n-10

Back to the equation:

-(2n-10)



We get rid of parentheses

n-2n+10+23=0

We add all the numbers together, and all the variables

-1n+33=0

We move all terms containing n to the left, all other terms to the right

-n=-33

n=-33/-1

n=+33

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