n+3-5=10-5n+4n

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Solution for n+3-5=10-5n+4n equation: 



n+3-5=10-5n+4n

We move all terms to the left:

n+3-5-(10-5n+4n)=0

We add all the numbers together, and all the variables

n-(-1n+10)+3-5=0

We add all the numbers together, and all the variables

n-(-1n+10)-2=0

We get rid of parentheses

n+1n-10-2=0

We add all the numbers together, and all the variables

2n-12=0

We move all terms containing n to the left, all other terms to the right

2n=12

n=12/2

n=6

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