n+3/n=19/4

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Solution for n+3/n=19/4 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

n+3/n = 19/4 // - 19/4

n+3/n-(19/4) = 0

n+3/n-19/4 = 0

1*n^1+3*n^-1-19/4*n^0 = 0

(1*n^2-19/4*n^1+3*n^0)/(n^1) = 0 // * n^2

n^1*(1*n^2-19/4*n^1+3*n^0) = 0

n^1

n^2+(-19/4)*n+3 = 0

n^2+(-19/4)*n+3 = 0

DELTA = (-19/4)^2-(1*3*4)

DELTA = 169/16

DELTA > 0

n = ((169/16)^(1/2)-(-19/4))/(1*2) or n = (-(-19/4)-(169/16)^(1/2))/(1*2)

n = 4 or n = 3/4

n in { 3/4, 4} 

n in { 3/4, 4 }

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