n+4+8n-10=2n+3+3(2n-1)

Solution for n+4+8n-10=2n+3+3(2n-1) equation:

n+4+8n-10=2n+3+3(2n-1)

We move all terms to the left:

n+4+8n-10-(2n+3+3(2n-1))=0

We add all the numbers together, and all the variables

9n-(2n+3+3(2n-1))-6=0


We calculate terms in parentheses: -(2n+3+3(2n-1)), so:

2n+3+3(2n-1)

determiningTheFunctionDomain
2n+3(2n-1)+3

We multiply parentheses

2n+6n-3+3

We add all the numbers together, and all the variables

8n

Back to the equation:

-(8n)


We add all the numbers together, and all the variables

n-6=0

We move all terms containing n to the left, all other terms to the right

n=6