n+5n+7=2(2n+1)+3n+2

Solution for n+5n+7=2(2n+1)+3n+2 equation:

n+5n+7=2(2n+1)+3n+2

We move all terms to the left:

n+5n+7-(2(2n+1)+3n+2)=0

We add all the numbers together, and all the variables

6n-(2(2n+1)+3n+2)+7=0


We calculate terms in parentheses: -(2(2n+1)+3n+2), so:

2(2n+1)+3n+2

We add all the numbers together, and all the variables

3n+2(2n+1)+2

We multiply parentheses

3n+4n+2+2

We add all the numbers together, and all the variables

7n+4

Back to the equation:

-(7n+4)


We get rid of parentheses

6n-7n-4+7=0

We add all the numbers together, and all the variables

-1n+3=0

We move all terms containing n to the left, all other terms to the right

-n=-3

n=-3/-1

n=+3