n+n+2+n+4=2(n+4)+12

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Solution for n+n+2+n+4=2(n+4)+12 equation: 



n+n+2+n+4=2(n+4)+12

We move all terms to the left:

n+n+2+n+4-(2(n+4)+12)=0

We add all the numbers together, and all the variables

3n-(2(n+4)+12)+6=0



We calculate terms in parentheses: -(2(n+4)+12), so:

2(n+4)+12

We multiply parentheses

2n+8+12

We add all the numbers together, and all the variables

2n+20

Back to the equation:

-(2n+20)



We get rid of parentheses

3n-2n-20+6=0

We add all the numbers together, and all the variables

n-14=0

We move all terms containing n to the left, all other terms to the right

n=14

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