n-(-12)+2(n+1)=20

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Solution for n-(-12)+2(n+1)=20 equation: 



n-(-12)+2(n+1)=20

We move all terms to the left:

n-(-12)+2(n+1)-(20)=0

determiningTheFunctionDomain
n+2(n+1)-20-(-12)=0

We add all the numbers together, and all the variables

n+2(n+1)-8=0

We multiply parentheses

n+2n+2-8=0

We add all the numbers together, and all the variables

3n-6=0

We move all terms containing n to the left, all other terms to the right

3n=6

n=6/3

n=2

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