n-(4+3n)=28

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Solution for n-(4+3n)=28 equation: 



n-(4+3n)=28

We move all terms to the left:

n-(4+3n)-(28)=0

We add all the numbers together, and all the variables

n-(3n+4)-28=0

We get rid of parentheses

n-3n-4-28=0

We add all the numbers together, and all the variables

-2n-32=0

We move all terms containing n to the left, all other terms to the right

-2n=32

n=32/-2

n=-16

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