n-1-4=3(3n-1)-(7n-3)

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Solution for n-1-4=3(3n-1)-(7n-3) equation: 



n-1-4=3(3n-1)-(7n-3)

We move all terms to the left:

n-1-4-(3(3n-1)-(7n-3))=0

We add all the numbers together, and all the variables

n-(3(3n-1)-(7n-3))-5=0



We calculate terms in parentheses: -(3(3n-1)-(7n-3)), so:

3(3n-1)-(7n-3)

We multiply parentheses

9n-(7n-3)-3

We get rid of parentheses

9n-7n+3-3

We add all the numbers together, and all the variables

2n

Back to the equation:

-(2n)



We add all the numbers together, and all the variables

-1n-5=0

We move all terms containing n to the left, all other terms to the right

-n=5

n=5/-1

n=-5

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