n-10+12n+7=-7(2+4n)-5(n+7)

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Solution for n-10+12n+7=-7(2+4n)-5(n+7) equation: 



n-10+12n+7=-7(2+4n)-5(n+7)

We move all terms to the left:

n-10+12n+7-(-7(2+4n)-5(n+7))=0

We add all the numbers together, and all the variables

n+12n-(-7(4n+2)-5(n+7))-10+7=0

We add all the numbers together, and all the variables

13n-(-7(4n+2)-5(n+7))-3=0



We calculate terms in parentheses: -(-7(4n+2)-5(n+7)), so:

-7(4n+2)-5(n+7)

We multiply parentheses

-28n-5n-14-35

We add all the numbers together, and all the variables

-33n-49

Back to the equation:

-(-33n-49)



We get rid of parentheses

13n+33n+49-3=0

We add all the numbers together, and all the variables

46n+46=0

We move all terms containing n to the left, all other terms to the right

46n=-46

n=-46/46

n=-1

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