n-10+12n+7=7(2+4n)-5(n+7)

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Solution for n-10+12n+7=7(2+4n)-5(n+7) equation: 



n-10+12n+7=7(2+4n)-5(n+7)

We move all terms to the left:

n-10+12n+7-(7(2+4n)-5(n+7))=0

We add all the numbers together, and all the variables

n+12n-(7(4n+2)-5(n+7))-10+7=0

We add all the numbers together, and all the variables

13n-(7(4n+2)-5(n+7))-3=0



We calculate terms in parentheses: -(7(4n+2)-5(n+7)), so:

7(4n+2)-5(n+7)

We multiply parentheses

28n-5n+14-35

We add all the numbers together, and all the variables

23n-21

Back to the equation:

-(23n-21)



We get rid of parentheses

13n-23n+21-3=0

We add all the numbers together, and all the variables

-10n+18=0

We move all terms containing n to the left, all other terms to the right

-10n=-18

n=-18/-10

n=1+4/5

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