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n-10=3(1/2n-10)
We move all terms to the left:
n-10-(3(1/2n-10))=0
Domain of the equation: 2n-10))!=0We multiply all the terms by the denominator
n∈R
n*2n-10*2n-10))-(3(1-10))=0
We add all the numbers together, and all the variables
n*2n-10*2n-10))-(3(-9))=0
We add all the numbers together, and all the variables
n*2n-10*2n=0
Wy multiply elements
2n^2-20n=0
a = 2; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·2·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*2}=\frac{0}{4} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*2}=\frac{40}{4} =10 $
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