n-2(3n+4)=-6(n-2)-1

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Solution for n-2(3n+4)=-6(n-2)-1 equation: 



n-2(3n+4)=-6(n-2)-1

We move all terms to the left:

n-2(3n+4)-(-6(n-2)-1)=0

We multiply parentheses

n-6n-(-6(n-2)-1)-8=0



We calculate terms in parentheses: -(-6(n-2)-1), so:

-6(n-2)-1

We multiply parentheses

-6n+12-1

We add all the numbers together, and all the variables

-6n+11

Back to the equation:

-(-6n+11)



We add all the numbers together, and all the variables

-5n-(-6n+11)-8=0

We get rid of parentheses

-5n+6n-11-8=0

We add all the numbers together, and all the variables

n-19=0

We move all terms containing n to the left, all other terms to the right

n=19

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