n-2(n+2)=-13+2n

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Solution for n-2(n+2)=-13+2n equation: 



n-2(n+2)=-13+2n

We move all terms to the left:

n-2(n+2)-(-13+2n)=0

We add all the numbers together, and all the variables

n-2(n+2)-(2n-13)=0

We multiply parentheses

n-2n-(2n-13)-4=0

We get rid of parentheses

n-2n-2n+13-4=0

We add all the numbers together, and all the variables

-3n+9=0

We move all terms containing n to the left, all other terms to the right

-3n=-9

n=-9/-3

n=+3

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