n-2(n-5)=-10n-(2-3n)

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Solution for n-2(n-5)=-10n-(2-3n) equation: 



n-2(n-5)=-10n-(2-3n)

We move all terms to the left:

n-2(n-5)-(-10n-(2-3n))=0

We add all the numbers together, and all the variables

n-2(n-5)-(-10n-(-3n+2))=0

We multiply parentheses

n-2n-(-10n-(-3n+2))+10=0



We calculate terms in parentheses: -(-10n-(-3n+2)), so:

-10n-(-3n+2)

We get rid of parentheses

-10n+3n-2

We add all the numbers together, and all the variables

-7n-2

Back to the equation:

-(-7n-2)



We add all the numbers together, and all the variables

-1n-(-7n-2)+10=0

We get rid of parentheses

-1n+7n+2+10=0

We add all the numbers together, and all the variables

6n+12=0

We move all terms containing n to the left, all other terms to the right

6n=-12

n=-12/6

n=-2

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