n-2/n-5=n+3/n-9

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Solution for n-2/n-5=n+3/n-9 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

n-(2/n)-5 = n+3/n-9 // - n+3/n-9

n-n-(2/n)-(3/n)-5+9 = 0

n-n-2*n^-1-3*n^-1-5+9 = 0

-5*n^-1 = -4 // : -5

n^-1 = 4/5

-1 < 0

1/(n^1) = 4/5 // * n^1

1 = 4/5*n^1 // : 4/5

5/4 = n^1

n = 5/4

n = 5/4

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