n-3(n-1.2)=4(n+1.6)

Solution for n-3(n-1.2)=4(n+1.6) equation:

n-3(n-1.2)=4(n+1.6)

We move all terms to the left:

n-3(n-1.2)-(4(n+1.6))=0

We multiply parentheses

n-3n-(4(n+1.6))+3.6=0


We calculate terms in parentheses: -(4(n+1.6)), so:

4(n+1.6)

We multiply parentheses

4n+6.4

Back to the equation:

-(4n+6.4)


We add all the numbers together, and all the variables

-2n-(4n+6.4)+3.6=0

We get rid of parentheses

-2n-4n-6.4+3.6=0

We add all the numbers together, and all the variables

-6n-2.8=0

We move all terms containing n to the left, all other terms to the right

-6n=2.8

n=2.8/-6

n=-1/2.1428571428571