n-3/n=26/3

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Solution for n-3/n=26/3 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

n-(3/n) = 26/3 // - 26/3

n-(3/n)-(26/3) = 0

n-3*n^-1-26/3 = 0

1*n^1-3*n^-1-26/3*n^0 = 0

(1*n^2-26/3*n^1-3*n^0)/(n^1) = 0 // * n^2

n^1*(1*n^2-26/3*n^1-3*n^0) = 0

n^1

n^2+(-26/3)*n-3 = 0

n^2+(-26/3)*n-3 = 0

DELTA = (-26/3)^2-(-3*1*4)

DELTA = 784/9

DELTA > 0

n = ((784/9)^(1/2)-(-26/3))/(1*2) or n = (-(-26/3)-(784/9)^(1/2))/(1*2)

n = 9 or n = -1/3

n in { -1/3, 9} 

n in { -1/3, 9 }

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