n-5(2n-9)=2(n-3)+6n

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Solution for n-5(2n-9)=2(n-3)+6n equation: 



n-5(2n-9)=2(n-3)+6n

We move all terms to the left:

n-5(2n-9)-(2(n-3)+6n)=0

We multiply parentheses

n-10n-(2(n-3)+6n)+45=0



We calculate terms in parentheses: -(2(n-3)+6n), so:

2(n-3)+6n

We add all the numbers together, and all the variables

6n+2(n-3)

We multiply parentheses

6n+2n-6

We add all the numbers together, and all the variables

8n-6

Back to the equation:

-(8n-6)



We add all the numbers together, and all the variables

-9n-(8n-6)+45=0

We get rid of parentheses

-9n-8n+6+45=0

We add all the numbers together, and all the variables

-17n+51=0

We move all terms containing n to the left, all other terms to the right

-17n=-51

n=-51/-17

n=+3

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