n-52=3/2(18+n)

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Solution for n-52=3/2(18+n) equation: 



n-52=3/2(18+n)

We move all terms to the left:

n-52-(3/2(18+n))=0



Domain of the equation: 2(18+n))!=0

n∈R



We add all the numbers together, and all the variables

n-(3/2(n+18))-52=0

We multiply all the terms by the denominator


n*2(n+18))-(3-52*2(n+18))=0

Wy multiply elements

2n^2(n-104n(n=0

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