n-5=(3n+1)/2

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Solution for n-5=(3n+1)/2 equation:



n-5=(3n+1)/2
We move all terms to the left:
n-5-((3n+1)/2)=0
We multiply all the terms by the denominator
n*2)-((3n+1)-5*2)=0
We add all the numbers together, and all the variables
n*2)-((3n+1)=0
Wy multiply elements
2n^2=0
a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{4}=0$

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