n/(n-12)=9/5

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Solution for n/(n-12)=9/5 equation: 


D( n )

n-12 = 0

n-12 = 0

n-12 = 0

n-12 = 0 // + 12

n = 12

n in (-oo:12) U (12:+oo)

n/(n-12) = 9/5 // - 9/5

n/(n-12)-(9/5) = 0

n/(n-12)-9/5 = 0

(5*n)/(5*(n-12))+(-9*(n-12))/(5*(n-12)) = 0

5*n-9*(n-12) = 0

108-4*n = 0

(108-4*n)/(5*(n-12)) = 0

(108-4*n)/(5*(n-12)) = 0 // * 5*(n-12)

108-4*n = 0

108-4*n = 0 // - 108

-4*n = -108 // : -4

n = -108/(-4)

n = 27

n = 27

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